Expand each of the following,using suitable i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We use the algebraic identity: $(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2yz + 2zx$.Comparing $(x + 2y + 4z)^2$ with the identity,we have $x = x$,$

Vedclass · Accepted Answer

$(x^2 + 4y^2 + 16z^2 + 4xy + 16yz + 8zx)$

Vedclass · Answer

(A) We use the algebraic identity: $(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2yz + 2zx$.Comparing $(x + 2y + 4z)^2$ with the identity,we have $x = x$,$y = 2y$,and $z = 4z$.Substituting these values into the identity:$(x + 2y + 4z)^2 = (x)^2 + (2y)^2 + (4z)^2 + 2(x)(2y) + 2(2y)(4z) + 2(4z)(x)$.Simplifying each term:$= x^2 + 4y^2 + 16z^2 + 4xy + 16yz + 8zx$.

Expand each of the following,using suitable identities: $(x + 2y + 4z)^2$

Similar Questions

Find the zero of the polynomial: $p(x) = x - 5$.

Find the remainder when $x^{3}+3x^{2}+3x+1$ is divided by $x-\frac{1}{2}$.

Write the coefficients of $x^2$ in each of the following:
$(i)$ $\frac{\pi}{2} x^2 + x$
$(ii)$ $\sqrt{2} x - 1$

Find the remainder when $x^{3}-ax^{2}+6x-a$ is divided by $x-a$.

Write the following cube in expanded form: $\left[x-\frac{2}{3} y\right]^{3}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module